Comments on: Representing Rotations In Quaternion Arithmetic

By: Simon Brown

Simon Brown — Fri, 13 May 2011 09:50:12 +0000

Thanks for reporting, that’s been broken for years! Fixed.

By: Marc

Marc — Thu, 12 May 2011 23:12:46 +0000

I think your definition of the conjugate is wrong.
You state that for q=(w,x,y,z) the conjugate q* is defined as q*=(x,-y,-z,-w).
The correct definition is q*=(w,-x,-y,-z).

Aside from that… great article

By: Simon Brown

Simon Brown — Fri, 27 Aug 2010 08:48:11 +0000

Thanks for letting me know, I’ve fixed the offending TeX syntax!

By: Daniel

Daniel — Wed, 25 Aug 2010 19:49:03 +0000

When I look at this posting, there are a number of places where it says Invalid Equation, where I would expect a graphic of an equation. Not a very encouraging sign!

By: Simon Brown

Simon Brown — Mon, 14 Dec 2009 09:21:21 +0000

Thanks, also fixed!

By: Dan

Dan — Sat, 12 Dec 2009 18:56:35 +0000

Second equation from the top, should be: i^2 = j^2 = k^2 = -1

By: Simon Brown

Simon Brown — Tue, 08 Dec 2009 16:02:33 +0000

In this case, p is just another quaternion rotation.

By: CALTABIANO Salvatore

CALTABIANO Salvatore — Thu, 03 Dec 2009 01:26:51 +0000

When you explaion rotation, you used “p”, WHAT’s “p” ??? Thank you

By: Arsham Atonyan

Arsham Atonyan — Sun, 23 Aug 2009 07:39:39 +0000

good post only q*=(w,-v)=(w,-x,-y,-z);

By: psp spiele

psp spiele — Sat, 28 Feb 2009 21:14:58 +0000

Good post, adding it to my bookmarks!